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题目描述:
解题思路:图的深度优先遍历
#include<bits/stdc++.h>
using namespace std;
void dfs(vector<vector<int>>& v,int i, int j,int& n) {
if (i<0 || i>=n || j<0 || j>=n || (v[i][j] == 0)) return;
v[i][j] = 0;
dfs(v, i - 1, j, n);
dfs(v, i + 1, j, n);
dfs(v, i, j-1, n);
dfs(v, i, j+1, n);
}
int main()
{
int n;
cin >> n;
vector<vector<int>> v(n, vector<int>(n));
for (int i = 0; i < n; ++i)
for (int j = 0; j < n; ++j)
cin >> v[i][j];
int cnt = 0;
for (int i = 0; i < n; ++i)
for (int j = 0; j < n; ++j) {
if (v[i][j]) {
++cnt;
dfs(v, i, j, n);
}
}
cout << cnt << endl;
return 0;
}

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