基于python利用os和py7zr库进行对文件名的修改和解压

问就是ss是第一生产力

自己学了python，了解了几个库，第一次尝试利用py处理计算机问题

代码如下

def rename_none_to_7z(folder_path):
    # 遍历指定文件夹中的所有文件
    password = "懂得都懂"
    for filename in os.listdir(folder_path):
        # 构建旧文件路径和新文件路径
        old_file_path = os.path.join(folder_path, filename)
 
        # 判断路径是否为文件
        if os.path.isfile(old_file_path):  # 如果是”文件夹“将不会执行
            # 执行文件名修改
            list1 = os.path.splitext(old_file_path)
            if list1[1] != ".7z":
                # 执行当list1的第一个元素不等于".7z"、不等于""、不等于".zip"的操作
                # 这里放置相应的代码
 
                new_file_path = old_file_path + ".7z"
                os.rename(old_file_path, new_file_path)
                print(f"Renamed: {old_file_path} -> {new_file_path}")
                print(new_file_path + "正在解压...")
                with py7zr.SevenZipFile(new_file_path, mode='r', password=password) as z:
                    extract_path = os.path.dirname(new_file_path)
                    z.extractall(path=extract_path)
                print(new_file_path + "解压完成...")
                os.remove(new_file_path)
                print(new_file_path + "删除完成...")
            else:
                print(old_file_path + "正在解压...")
                with py7zr.SevenZipFile(old_file_path, mode='r', password=password) as z:
                    extract_path = os.path.dirname(old_file_path)
                    z.extractall(path=extract_path)
                print(old_file_path+"解压完成...")
                os.remove(old_file_path)
                print(old_file_path+"删除完成...")
        else:
            print(filename + " is not a file")
            rename_none_to_7z(old_file_path)
rename_none_to_7z("文件目录路径")