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比赛的时候老师总是说,你们连高职都打不过。
题目都很简单,就直接贴一下代码吧,有的用C++写的,有的用Python写的。
print("ni ye lai can jia RoboCom a?")
#include<bits/stdc++.h>
using namespace std;
signed main(){
int A,B,C,D,a,b,c;
cin>>A>>B>>C>>D>>a>>b>>c;
cout<<"Diff = "<<A-a<<", "<<B-b<<", "<<C-c<<"\n";
if (abs(A-a) + abs(B-b) + abs(C-c) <= D)
cout<<"Yes";
else
cout<<"No";
return 0;
}
#include<bits/stdc++.h>
using namespace std;
int n;
string s[13] = {"","January","February","March","April","May","June",
"July","August","September","October","November","December"};
signed main(){
while (cin>>n){
if (n > 12 || n < 1)
break;
cout<<s[n]<<"\n";
}
cout<<"?";
return 0;
}
#include<bits/stdc++.h> using namespace std; signed main(){ int n;cin>>n; while(n--){ string s;cin>>s;bool f = true; for (int i = 0; i < s.length() - 1; ++i) { if (islower(s[i])){ if (!(s[i + 1] == s[i] - 1 || toupper(s[i]) == s[i + 1])){ f = false;break; } } else if (!(tolower(s[i]) == s[i + 1] || s[i + 1] == s[i] + 1)){ f = false;break; } } if (f) cout<<"Y\n"; else cout<<"N\n"; } return 0; }
#include<bits/stdc++.h> using namespace std; #define int long long bool check(int x){ int k = 0,kk = x; while (kk){ kk /= 10; k += 1; } if (k % 2 != 0) return false; k = pow(10,k / 2); if (x % k - 1 == x / k) return true; return false; } signed main(){ int n;cin>>n; while(n--){ int m,k = 0; cin>>m; if (check(m)){ k += 1; if (ceil(sqrt(m)) * ceil(sqrt(m)) == m) k += 1; } cout<<k<<"\n"; } return 0; }
新浪微博上有网友发文称:“朋友买了本玻尔X海森堡的物理大佬同人本,送了300道高数题。更绝的是,要做完题目按照答案涂答题卡,涂出一个二维码,扫描二维码才能看到特典,做错了就看不到了……”那张传说中的答题卡如下图所示:若答案为 4 位整数(位数不足时在前面补足 0),则前两位为横坐标,后两位为纵坐标。若一题有两小问,则第一问答案为横坐标,第二问答案为纵坐标。若答案为分数,则分子为横坐标,分母为纵坐标。
本题就请你根据答案帮助读者填写答题卡。
ch = [['.'] * 105 for i in range(105)] n, m = map(int,input().split()) for i in range(m): s = input() if s.count(';'): a, b = map(int,s.split(';')) col = a row = n - b + 1 ch[row][col] = '#' elif s.count('/'): a, b = map(int,s.split('/')) col = a row = n - b + 1 ch[row][col] = '#' else: a = int(s) b = a % 100 a //= 100 col = a row = n - b + 1 ch[row][col] = '#' for i in range(1,n + 1): for j in range(1,n + 1): print(ch[i][j],end='') print()
s = set()
n = int(input())
for i in range(n):
s.add(input())
m = int(input())
for i in range(m):
s.remove(input())
s = list(s)
s.sort(reverse=True)
for i in s:
print(i)
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