当前位置:   article > 正文

代码随想录算法训练营第56天|583. 两个字符串的删除操作 72. 编辑距离 编辑距离总结

代码随想录算法训练营第56天|583. 两个字符串的删除操作 72. 编辑距离 编辑距离总结

583. 两个字符串的删除操作

  1. class Solution {
  2. public:
  3. int minDistance(string word1, string word2) {
  4. vector<vector<int>> dp(word1.size() + 1, vector<int> (word2.size() + 1, 0));
  5. for (int i = 0; i <= word1.size(); i++) dp[i][0] = i;
  6. for (int j = 0; j <= word2.size(); j++) dp[0][j] = j;
  7. for (int i = 1; i <= word1.size(); i++) {
  8. for (int j = 1; j <= word2.size(); j++) {
  9. if (word1[i - 1] == word2[j - 1]) {
  10. dp[i][j] = dp[i - 1][j - 1];
  11. }else {
  12. dp[i][j] = min(dp[i - 1][j] + 1, dp[i][j - 1] + 1);
  13. }
  14. }
  15. }
  16. return dp[word1.size()][word2.size()];
  17. }
  18. };

72. 编辑距离

  1. class Solution {
  2. public:
  3. int minDistance(string word1, string word2) {
  4. vector<vector<int>> dp(word1.size() + 1, vector<int>(word2.size() + 1, 0));
  5. for (int i = 0; i <= word1.size(); i++) dp[i][0] = i;
  6. for (int j = 0; j <= word2.size(); j++) dp[0][j] = j;
  7. for (int i = 1; i <= word1.size(); i++) {
  8. for (int j = 1; j <= word2.size(); j++) {
  9. if (word1[i - 1] == word2[j - 1]) {
  10. dp[i][j] = dp[i - 1][j - 1];
  11. }
  12. else {
  13. dp[i][j] = min({dp[i - 1][j - 1], dp[i - 1][j], dp[i][j - 1]}) + 1;
  14. }
  15. }
  16. }
  17. return dp[word1.size()][word2.size()];
  18. }
  19. };

编辑距离总结

声明:本文内容由网友自发贡献,不代表【wpsshop博客】立场,版权归原作者所有,本站不承担相应法律责任。如您发现有侵权的内容,请联系我们。转载请注明出处:https://www.wpsshop.cn/w/羊村懒王/article/detail/214816
推荐阅读
相关标签
  

闽ICP备14008679号