华为OD机试真题-围棋的气-2023年OD统一考试（C卷）---python代码_华为题"围棋的气"python答案

题目：

代码：

"""
# 输入：2的倍数
第一个为行号 0-18
第二个为列号 0-18

第一行为黑色
第二行为白色

思路：先求黑色，进行去重+棋子的位置，再求白色
逐个棋子求坐标。
"""
def get_item(a):
    temp = list()
    for item in a:
        row = item[0]
        column = item[1]
        if row - 1 >= 0:
            temp.append([row - 1, column])
        if column - 1 >= 0:
            temp.append([row, column - 1])
        if row + 1 <= 18:
            temp.append([row + 1, column])
        if column + 1 <= 18:
            temp.append([row, column + 1])
    return temp


# 输入不固定，2的整数倍
b = list(map(int, input().split()))
w = list(map(int, input().split()))
black = [b[i:i+2] for i in range(0, len(b), 2)]
white = [w[i:i+2] for i in range(0, len(w), 2)]
# black = [[0,5], [8,9], [9,10]]
# white = [[5,0], [9,9], [9,8]]

temp_black = get_item(black)
temp_white = get_item(white)
# 将子列表转换为元组并用set去重，然后再转换回列表
black_set_temp = set(tuple(sublist) for sublist in temp_black)
white_set = set(tuple(sublist) for sublist in white)
black_set = set(tuple(sublist) for sublist in black)
# 求当前黑色棋子红周围的气与白色求交集，求当前黑色的周围的气与本身黑色的交集，这两个交集求并集，用当前黑色棋子周围的气求并集的差集
black_res = black_set_temp - ((black_set_temp & white_set) | (black_set_temp & black_set))

white_set_temp = set(tuple(sublist) for sublist in temp_white)

white_res = white_set_temp - ((white_set_temp & black_set) | (white_set_temp & white_set))
# 本身去重
print(len(black_res), black_res)
print(len(white_res), white_res)
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