Easyx-----c++实现控制台井字棋简单人机对弈_c++井字棋人机

 main.cpp

#include"TicTacToe.h"
int main() 
{
	Game game;
	game.getWinner();
	return 0;
	
}

 TicTacToe.h

#pragma once
#include<iostream>
using namespace std;
#include<array>
#include<ctime>
class Game
{
public:
	Game();
	void print();
	char getCurrentPlayer();
	void getWinner();
	bool isDone(int row,int col);
	void makeMove();
	void computer_move(int row, int col);
protected:
 
	array <array< char, 3 >, 3 > board;
	int row;
	int col;
};

TicTacToe.cpp

#include"TicTacToe.h"
Game::Game()
{
	for (int i = 0; i < 3; i++)
	{
		for (int j = 0; j < 3; j++)
		{
			board[i][j] = '-';
		}
	} 
	this->col = 3;
	this->row = 3;
}
 
void Game::print()
{
	cout << "\t1\t2\t3\n";
	for (int i = 0; i < 3; i++)
	{
 
		cout << i + 1;
		for (int j = 0; j < 3; j++)
		{
			cout << "\t";
			cout << board[i][j];
		}
		cout << endl;
	}
}
 
 
char Game::getCurrentPlayer()
{
 
	int i = 0;
	for (; i < 3; i++)//判断第i行是否全都相同
	{
		if (board[i][0] == board[i][1] && board[i][1] == board[i][2] && board[i][0] != '-')
			return board[i][0];//将第i行的内容返回
	}
	for (i = 0; i < 3; i++)//判断第i列是否全都相同
	{
		if (board[0][i] == board[1][i] && board[1][i] == board[2][i] && board[0][i] != '-')
			return board[0][i];//将第i列的内容返回
	}
	if (board[0][0] == board[1][1] && board[1][1] == board[2][2] && board[0][0] != '-')//判断捺对角线（\）的内容是否全都相同
		return board[0][0];
	else if (board[0][2] == board[1][1] && board[1][1] == board[2][0] && board[0][2] != '-')//判断撇对角线（/）的内容是否全都相同
		return board[0][2];
	else if (isDone(row,col))//判断是否是平局，如果是平局返回‘q’
		return 'q';
	else //判断是否还未产生游戏结果，如果还未产生游戏结果返回‘-’
		return '-';
}
 
void Game::getWinner()
{
	char a;
		do
		{
			print();						//屏幕上打印一个棋盘
			makeMove();						//打印出棋盘之后，玩家开始下棋
			a = getCurrentPlayer();		    //玩家下完棋后，开始判断游戏结果
			if (a != '-')				    //  ‘-’：没人赢
			{
				break;						//如果已经分出胜负，跳出循环
			}
			computer_move(row,col);			//如果没有分出胜负，电脑下棋
			a = getCurrentPlayer();			//下完之后判断游戏结果
		} while (a == '-');
		if (a == 'X')						//判断玩家是否获胜：‘x’代表玩家获胜
			printf("Congratulations,you win!\n");
		else if (a == 'O')					//判断玩家是否获胜：‘o’代表电脑获胜
			printf("It's too bad,you lose!\n");
		else								//判断是否是平局
			printf("Draw!\n");
}
 
bool Game::isDone(int row,int col)
{
 
	//判断数组当中每一个元素是否有'-'，如果有'-'，说明没有满，返回0；否则返回1
	int i, j;
	for (i = 0; i < row; i++)
	{
		for (j = 0; j < col; j++)
			if (board[i][j] == '-')	//判断是否有'-'
				return 0;			//有'-'返回0
	}
	return 1;						//没有'-'返回1
}
 
void Game::makeMove()
{
 
		int x, y;//先定义两个变量，以便接收玩家下棋的坐标
		do
		{
			printf("Please input your coordinate:(x,y)!");//提示玩家下棋
			scanf("%d%d", &x, &y);						  //接收玩家所下的位置
			if (x >= 1 && x <= 3 && y >= 1 && y <= 3)	  //判断玩家输入坐标是否有误
				if (board[x - 1][y - 1] == '-')			  //判断玩家输入的位置是否已经被占
				{
					board[x - 1][y - 1] = 'X';			  //将玩家输入的位置用‘x’占用
					break;
				}
				else//玩家输入位置被占，提示玩家重新输入位置
					printf("Error!This place was be used!\n");
			else//玩家输入坐标有误，直接提示玩家error
				printf("Error!");
		} while (1);
	
}
void Game::computer_move(int row,int col)
{
	srand((unsigned long)time(NULL));//利用函数生成随机数
	do
	{
		int x = rand() % row;//控制随机数小于3并把结果赋给横坐标
		int y = rand() % col;//控制随机数小于3并把结果赋给纵坐标
		if (board[x][y] == '-')//判断电脑选择的位置是否被占
		{
			board[x][y] = 'O';//将电脑下棋的位置用‘O’占用
			break;
		}
	} while (1);
}