base64编解码的两个函数,声明,参考网络上的代码实现。
- unsigned char *base64_encode(unsigned char *str, long* lpBufLen)
- {
- long len;
- long str_len;
- unsigned char *res;
- int i,j;
- //定义base64编码表
- const unsigned char *base64_table = (const unsigned char *)("ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/");
-
- //计算经过base64编码后的字符串长度
- str_len=strlen((char*)str);
- if(str_len % 3 == 0)
- len=str_len/3*4;
- else
- len=(str_len/3+1)*4;
-
- if (NULL != lpBufLen) {
- *lpBufLen = len;
- }
-
- res = (unsigned char *)malloc(sizeof(unsigned char)*len+1);
- res[len]='\0';
-
- //以3个8位字符为一组进行编码
- for(i=0,j=0;i<len-2;j+=3,i+=4)
- {
- res[i]=base64_table[str[j]>>2]; //取出第一个字符的前6位并找出对应的结果字符
- res[i+1]=base64_table[(str[j]&0x3)<<4 | (str[j+1]>>4)]; //将第一个字符的后位与第二个字符的前4位进行组合并找到对应的结果字符
- res[i+2]=base64_table[(str[j+1]&0xf)<<2 | (str[j+2]>>6)]; //将第二个字符的后4位与第三个字符的前2位组合并找出对应的结果字符
- res[i+3]=base64_table[str[j+2]&0x3f]; //取出第三个字符的后6位并找出结果字符
- }
-
- switch(str_len % 3)
- {
- case 1:
- res[i-2]='=';
- res[i-1]='=';
- break;
- case 2:
- res[i-1]='=';
- break;
- }
-
- return res;
- }
-
- unsigned char *base64_decode(unsigned char *code, long* lpBufLen)
- {
- //根据base64表,以字符找到对应的十进制数据
- int table[]={0,0,0,0,0,0,0,0,0,0,0,0,
- 0,0,0,0,0,0,0,0,0,0,0,0,
- 0,0,0,0,0,0,0,0,0,0,0,0,
- 0,0,0,0,0,0,0,62,0,0,0,
- 63,52,53,54,55,56,57,58,
- 59,60,61,0,0,0,0,0,0,0,0,
- 1,2,3,4,5,6,7,8,9,10,11,12,
- 13,14,15,16,17,18,19,20,21,
- 22,23,24,25,0,0,0,0,0,0,26,
- 27,28,29,30,31,32,33,34,35,
- 36,37,38,39,40,41,42,43,44,
- 45,46,47,48,49,50,51
- };
- long len;
- long str_len;
- unsigned char *res;
- int i,j;
-
- //计算解码后的字符串长度
- len=strlen((char*)code);
- //判断编码后的字符串后是否有=
- if(strstr((char*)code,"=="))
- str_len=len/4*3-2;
- else if(strstr((char*)code,"="))
- str_len=len/4*3-1;
- else
- str_len=len/4*3;
-
- if (NULL != lpBufLen) {
- *lpBufLen = str_len;
- }
-
- res=(unsigned char*)malloc(sizeof(unsigned char)*str_len+1);
- res[str_len]='\0';
-
- //以4个字符为一位进行解码
- for(i=0,j=0;i < len-2;j+=3,i+=4)
- {
- res[j]=((unsigned char)table[code[i]])<<2 | (((unsigned char)table[code[i+1]])>>4); //取出第一个字符对应base64表的十进制数的前6位与第二个字符对应base64表的十进制数的后2位进行组合
- res[j+1]=(((unsigned char)table[code[i+1]])<<4) | (((unsigned char)table[code[i+2]])>>2); //取出第二个字符对应base64表的十进制数的后4位与第三个字符对应bas464表的十进制数的后4位进行组合
- res[j+2]=(((unsigned char)table[code[i+2]])<<6) | ((unsigned char)table[code[i+3]]); //取出第三个字符对应base64表的十进制数的后2位与第4个字符进行组合
- }
-
- return res;
-
- }